Question

A container of Carbon Dioxide has a pressure of 755 mmHg at 325K. If the temperaure is decreased to 295K, what is the pressure of the gas in the container? (P2 = 685 mmHg

Answer 1

Answer on Question #83812 – Chemistry – General Chemistry

Question

A container of Carbon Dioxide has a pressure of $755\,\mathrm{mmHg}$ at $325\,K$. If the temperature is decreased to $295\,K$, what is the pressure of the gas in the container?

Solution

For comparing the sample of gas under two different conditions, the combined gas law can be used:

$$\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}.$$

The volume of container does not change ($V_1 = V_2$), therefore it can be reduced:

$$\frac{P_1}{T_1} = \frac{P_2}{T_2} \text{ (Gay - Lussac's law)}.$$

Then,

$$P_2 = \frac{P_1 T_2}{T_1} = \frac{755\,\mathrm{mmHg} \times 295\,K}{325\,K} \approx 685.3\,\mathrm{mmHg}.$$

Answer: If the temperature equals $295\,K$, the pressure equals $685.3\,\mathrm{mmHg}$.

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