Answer to Question #83510 in General Chemistry for Trevor

General Chemistry

Question #83510

What volume would 1.90 × 1023 molecules of an ideal gas occupy at STP?

Expert's answer

Answer:

n = N/Na = 1.90x10^23 / 6.02x10^23 = 0.306 mole

V = n*Vm

V = 0.306*22.4 = 6.86 litre

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