Answer to Question #83349 in General Chemistry for yo

General Chemistry

Question #83349

How many moles of NaOH are present in 18.0 mL of 0.230 M NaOH?

Expert's answer

Solution.

C = n/V n= CV

n(NaOH) = 0.018*0.23 =0.004 moles

Answer. 0.004 moles

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