Answer on Question #83276, Chemistry/ General Chemistry
The reaction A (aq) ---> B (aq) is a first order reaction with respect to A (aq). The concentration of A (aq) is reduced to 30.2% of its initial value 1.50 minutes. What is the value of the half-life (in s) of the reaction?
Solution
For the first order reaction
[A]=[A]*e-kt
[A]/[A] = e-kt
ln([A]/[A]) = -kt
Find k:
[A]/[A] = 0.302, t = 1.50 min = 110 s
ln(0.302) = -k*110
k= 0.0109
For the first order reaction the value of the half-life is:
t1/2 = ln2/k = ln2/0.0109 = 63.6 (s)
Answer: 63.6 s
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