Question #83262

The first reaction in the deployment of an automobile airbag is the decomposition of the solid binary ionic compound, sodium azide, into two products: nitrogen gas and sodium metal. What mass of sodium metal will form from the complete decomposition of 130 grams of sodium azide? Steps: (a) Write a balanced equation
(b) Use a conversion pathway calculation, starting with mass (g) of sodium azide ... #moles sodium azide#moles sodium metal productmass (g) sodium metal product.
1

Expert's answer

2018-12-27T06:27:09-0500

Question #83262, Chemistry / General chemistry

The first reaction in the deployment of an automobile airbag is the decomposition of the solid binary ionic compound, sodium azide, into two products: nitrogen gas and sodium metal. What mass of sodium metal will form from the complete decomposition of 130 grams of sodium azide? Steps: (a) Write a balanced equation

(b) Use a conversion pathway calculation, starting with mass (g) of sodium azide ...♦ #moles sodium azide♦#moles sodium metal product♦ mass (g) sodium metal product.

Solution

2NaN3=2Na+3N22 \mathrm{NaN_3} = 2 \mathrm{Na} + 3 \mathrm{N_2}M(NaN3)=23+143=65 (g/mol)M(\mathrm{NaN_3}) = 23 + 14 \cdot 3 = 65\ (\mathrm{g/mol})n(NaN3)=m/M=130/65=2 (mol)n(\mathrm{NaN_3}) = \mathrm{m/M} = 130 / 65 = 2\ (\mathrm{mol})n (Na)=n(NaN3)=2 moln\ (\mathrm{Na}) = n(\mathrm{NaN_3}) = 2\ \mathrm{mol}m (Na)=nM=232=46 (g)m\ (\mathrm{Na}) = n \cdot M = 23 \cdot 2 = 46\ (\mathrm{g})

Answer

m (Na)=46 gm\ (\mathrm{Na}) = 46\ \mathrm{g}


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