Answer to Question #82875 in General Chemistry for Felesha Phillips

Question

If 1.00 g of liquid benzene (C6H6) is added to a 3.81 L flask at 25 °C (the vapor pressure benzene = 92 mm Hg at 25 °C). What is the final pressure of benzene in the flask in mm Hg?

Answer 1

Answer:

PV = nRT

P = 0.01*8.31*298 / 0.00381 = 6499.68 АТМ = 48.75 mm Hg

P final = 140.75 mm Hg