Question #82003

What is the change in internal energy of a system (ΔU) if 5.15 kJ of heat energy is absorbed by the system and 2844 J of work is done on the system (by the surroundings) for a certain process?

Express your final answer in kJ.

Expert's answer

Answer on Question #82003, Chemistry / General Chemistry

What is the change in internal energy of a system (ΔU) if 5.15 kJ of heat energy is absorbed by the system and 2844 J of work is done on the system (by the surroundings) for a certain process?

Express your final answer in kJ.

Solution

According to the first law of thermodynamics: the change in the internal energy ΔU of a closed system is equal to the amount of heat Q supplied to the system, plus the amount of work W done on the system by its surroundings.


ΔU=Q+W\Delta U = Q + WΔU=5.15+2.844=7.994 kJ\Delta U = 5.15 + 2.844 = 7.994 \text{ kJ}


Answer

7.994 kJ is the change in internal energy of a system.

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