Question

(a) Calculate the molarity of a solution made by dissolving 0.0715 mol Na2SO4 in enough water to form 650 mL of solution.


Answer to correct significant figures WebAssign will check your answer for the correct number of significant figures. M
(b) How many moles of KMnO4 are present in 50.0 mL of a 0.0950 M solution?


Answer to correct significant figures WebAssign will check your answer for the correct number of significant figures. mol
(c) How many milliliters of 10.6 M HCl solution are needed to obtain 0.105 mol of HCl?


Answer to correct significant figures WebAssign will check your answer for the correct number of significant figures.

Answer 1

Question # 81373

(a) Calculate the molarity of a solution made by dissolving 0.0715 mol Na₂SO₄ in enough water to form 650 mL of solution. Answer to correct significant figures WebAssign will check your answer for the correct number of significant figures. M

(b) How many moles of KMnO₄ are present in 50.0 mL of a 0.0950 M solution? Answer to correct significant figures WebAssign will check your answer for the correct number of significant figures. Mol

(c) How many milliliters of 10.6 M HCl solution are needed to obtain 0.105 mol of HCl? Answer to correct significant figures WebAssign will check your answer for the correct number of significant figures.

Answer:

(a) The molarity of the resulting Na₂SO₄ solution is equal to 0.11 M.

$$C_M = \frac{0.0715}{0.650} = 0.11 \, M$$

(b) 0.00475 mol of KMnO₄ was provided in 50.0 mL of a 0.0950 M KMnO₄ solution.

$$\theta = 0.0950 \times 0.050 = 0.00475 \, \text{mol}$$

(c) To obtain 0.105 mol in a sample of 10.6 M HCl solution, 9.906 mL of this solution is required.

$$V = \frac{0.105}{10.6} \times 1000 = 9.906 \, \text{mL}$$