Question #80946

A major component of gasoline is octane . When octane is burned in air, it chemically reacts with oxygen gas to produce carbon dioxide and water .
What mass of carbon dioxide is produced by the reaction of 7.9g of octane?

Round your answer to 2 significant digits.

Expert's answer

A major component of gasoline is octane. When octane is burned in air, it chemically reacts with oxygen gas to produce carbon dioxide and water.

What mass of carbon dioxide is produced by the reaction of 7.9g of octane?

Solution:


2C8H18+30a16CO2+18H2O2 C _ {8} H _ {1 8} + 3 0 a \rightarrow 1 6 C O _ {2} + 1 8 H _ {2} Om(C8H18)=7.9gn(C8H18)=mM=7.9g(8.12011+18×1.008)g/moles=7.9g114.152g=0.06921moles\begin{array}{l} m \left(C _ {8} H _ {1 8}\right) = 7. 9 g \\ n \left(C _ {8} H _ {1 8}\right) = \frac {m}{M} = \frac {7 . 9 g}{(8 . 1 2 0 1 1 + 1 8 \times 1 . 0 0 8) g / m o l e s} \\ = \frac {7 . 9 g}{1 1 4 . 1 5 2 g} = 0. 0 6 9 2 1 m o l e s \\ \end{array}n(cO2)=0.06921×162=0.5537molesm(cO2)=0.5537moles×44.01g/moles=24.37g24.4g\begin{array}{l} n \left(c O _ {2}\right) = \frac {0 . 0 6 9 2 1 \times 1 6}{2} = 0. 5 5 3 7 m o l e s \\ m \left(c O _ {2}\right) = 0. 5 5 3 7 m o l e s \times 4 4. 0 1 g / m o l e s \\ = 2 4. 3 7 g \approx 2 4. 4 g \\ \end{array}


Answer: 24.4g.

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