Question #80762
In an acid - base titration involving sulphuric acid (H2SO4) and sodium hydroxide (NaOH) solution, 25ml of 0.02m sulphuric acid is required to completely neutralise 20ml of (NaOH) solution.
What is the molarity (mol/L) of NaOH solution?
What is the molarity (mol/L) of NaOH solution?
Expert's answer
Answer:
H2SO4 + 2NaOH = Na2SO4 + 2H2O
Moles of H2SO4 = 25.00*10-3 x 0.02 mol*L-1 = 0.5 x 10-3 mol
[NaOH] = 2*0.5*10-3 mol / 10*10-3 = 0.1 mol*L-1
H2SO4 + 2NaOH = Na2SO4 + 2H2O
Moles of H2SO4 = 25.00*10-3 x 0.02 mol*L-1 = 0.5 x 10-3 mol
[NaOH] = 2*0.5*10-3 mol / 10*10-3 = 0.1 mol*L-1
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#340153 on Dec 2023
#340153 on Dec 2023
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