Atoms of 4 non-metallic elements in the same group of the periodic table are arranged in order of increasing atomic radius as R<T<W<X which of the elements
i. Would easily lose e(s) from the uttermost shell
ii. Is most electronegative
iii. Would That displace from aqueous solution. Give a reason.
iv. Is at the top of the group
v. Has least electron affinity
vi. Is most oxidizing
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Expert's answer
2018-09-11T07:15:47-0400
Answer: i. Would easily lose e(s) from the uttermost shell – this is X, this element is iodine (J) ii. R – is most electronegative, this element is fluorine (F) iii. Fluorine would other halogens displace from aqueous solution, because fluorine so much powerful oxidizing element than other halogens. iv. Fluorine F is at the top of the group. v. Iodine (J) has least electron affinity. vi. Fluorine (F) is most oxidizing. So this four elements are F < Cl < Br < J
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