Answer to Question #80569 in General Chemistry for Alp

Question

Sodium hydroxide (NaOH) reacts with hydrochloric acid (HCl) to form sodium chloride (NaCl) and water (H2O) according to the equation below.
Given the atomic masses: Na = 23, O = 16, and H = 1
NaOH(aq) + HCl(aq)  NaCl(aq) + H2O(l)
Which substance will be in excess if 10g of sodium hydroxide reacts with 10g of hydrochloric acid?

Answer 1

m(NaOH) = 10 g
M(NaOH) = 23 + 16 +1 = 40 g/mol
n(NaOH) = m/M = 10g/40g/mol = 0.25 mol
m(HCl) = 10 g
M(HCl) = 1 + 35.5 = 36.5 g/mol
n(HCl) = 10g/36.5g/mol = 0.27 mol
According to the equation 1 mol NaOH reacts with 1 mol HCl.
HCl will be in excess.