Question

The balanced equation below shows the burning of methane in air.
CH4(g) + 2O2(g)  CO2(g) + H2O(l)
How many grams of carbon dioxide will be produced when 1 mole of methane burns completely?
Given the atomic masses:
C = 12, H = 1, and O = 16

Answer 1

n (CH₄) = 1 mole

M (CO₂) = Ar(C) + Ar(O) * 2 = 12 + 16 * 2 = 44

1 mole x g

CH₄ + 2 O₂ = CO₂ + 2 H₂O

1 mole 44

m (CO₂) = (1 * 44) / 1 = 44 g

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