Question

Ammonia can be reacted with carbon dioxide to form urea, as shown below. If 170 g ammonia were consumed in a reaction with excess carbon dioxide, what mass of urea could be produce?
The molar mass of ammonia is 17g/mole and that of urea is 60g/mole.
2NH3 + CO2 —> CO(NH2)2 + H2O

Answer 1

Ammonia can be reacted with carbon dioxide to form urea, as shown below. If 170 g ammonia were consumed in a reaction with excess carbon dioxide, what mass of urea could be produced?

The molar mass of ammonia is 17 g/mole and that of urea is 60 g/mole.

$$2 \mathrm{NH_3} + \mathrm{CO_2} \longrightarrow \mathrm{CO(NH_2)_2} + \mathrm{H_2O}$$

Solution:

1. $n = \frac{m}{M}$;

$$n(\mathrm{NH_3}) = \frac{170\ \mathrm{g}}{17\ \mathrm{g/mole}} = 10\ \mathrm{mole}.$$

2. $n(\mathrm{CO(NH_2)_2}) = \frac{1}{2} \times n(\mathrm{NH_3})$. It is from the equation of reaction;

$$n(\mathrm{CO(NH_2)_2}) = \frac{1}{2} \times 10\ \mathrm{mole} = 5\ \mathrm{mole};$$

3. $m = n \times M$;

$$m(\mathrm{CO(NH_2)_2}) = 5\ \mathrm{mole} \times 60\ \frac{\mathrm{g}}{\mathrm{mole}} = 300\ \mathrm{g}.$$

Answer: $m(\mathrm{CO(NH_2)_2})$ is 300 gram.

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