Answer to Question #79786 in General Chemistry for Sulaiman

Question

.60g of aluminum sulfate is produced when aluminum metal reacted with dilute sulfuric acid petrified is the law of conservation of mass is obeyed?
[Al=27,S=30, O=16, H=1].

Answer 1

.60g of aluminum sulfate is produced when aluminum metal reacted with dilute sulfuric acid petrified is the law of conservation of mass is obeyed?
[Al=27,S=30, O=16, H=1].

Answer:
2Al + 3H2SO4 = Al2(SO4)3 + 3H2(g)
M=342 g/moll (Al2(SO4)3)
m1=60 g (Al2(SO4)3) = 60/342=0.1754 moll
m2= ? (Aluminum)
2 moll aluminum --------- 1 moll aluminum sulfate
X moll aluminum --------- 0.1754 moll aluminum sulfate
X= (0.1754 x 2) / 1
X= 0.3508 moll aluminum = 0.3508 x 27 = 9.4716
Y= 0.1754 x 3 x 98 = 51.5676 g dilute sulfuric acid
Z= 0.1754 x 3 x 2= 1.0524 g hydrogen

Law of conservation of mass:
m(Al) + m(H2SO4)=m(Al2(SO4)3) + m(H2)
9.4716 + 51.5676 = 61 (about)
60 + 1.0524 = 61 (about)