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Answer to Question #79572 in General Chemistry for brad
Question #79572
a sample of glucose, C6H12O6, contains 1.250*10^21 carbon atoms: how many molecules of glucose does it contain
isn’t it just 2.083*10^20
isn’t it just 2.083*10^20
Expert's answer
Answer:
(1.250*10^21)*(1 glucose molecule / 6 C atoms) = 2.083*10^20 glucose molecules
(1.250*10^21)*(1 glucose molecule / 6 C atoms) = 2.083*10^20 glucose molecules
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