Answer to Question #79162 in General Chemistry for abigail

Question #79162
At 25 ∘C phosphoric acid, H3PO4, has the following equilibrium constants:
H3PO4(aq)+H2O(l)H2PO4−(aq)+H2O(l)HPO42−(aq)+H2O(l)⇌⇌⇌H3O+(aq)+H2PO−4(aq)H3O+(aq)+HPO42−(aq)H3O+(aq)+PO43−(aq) Ka1Ka2Ka3===7.5×10−36.2×10−84.2×10−13

What is the pH of a solution of 0.900 M KH2PO4, potassium dihydrogen phosphate?
1
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2018-07-19T06:54:58-0400
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