Question #78802

A pipette was used to deliver 19.05 mL of HCl to a flask that was subsequently titrated against NaOH. The concentration of NaOH was 0.1046 ± 0.0003 M. The volume of NaOH delivered from the burette was 19.48 ± 0.049 mL. Calculate the concentration of HCl. Please report an answer accurate to four decimal places. Report your answer in mol/L (M) but do not include the units when entering your answer and do not use Scientific notation.
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Expert's answer

2018-07-02T07:54:00-0400

A pipette was used to deliver 19.05 mL of HCl to a flask that was subsequently titrated against NaOH. The concentration of NaOH was 0.1046 ± 0.0003 M. The volume of NaOH delivered from the burette was 19.48 ± 0.049 mL. Calculate the concentration of HCl. Please report an answer accurate to four decimal places. Report your answer in mol/L (M) but do not include the units when entering your answer and do not use Scientific notation.

Solution:

We calculate the required concentration of HCl according to the law of multiple proportions:


N(NaOH)×V(NaOH)=N(HCl)×V(HCl), N - Normality.N(NaOH) \times V(NaOH) = N(HCl) \times V(HCl), \text{ N - Normality.}N(HCl)=M(HCl)=0.1046×19.4819.05=0.1070MN(HCl) = M(HCl) = \frac{0.1046 \times 19.48}{19.05} = 0.1070M


Answer: 0.1070.

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