Calculate the mass of ethyl chloride formed if 4.66 g of ethylene reacts with an 89.4% yield
Reaction equation:
C2H4 + HCl ---C2H5Cl
Number of moles of ethylene = 4.66 g / 28.05 g/mol = 0.17 moles, therefore
Number of moles of ethyl chloride = 0.17 moles;
Mass of ethyl chloride = 0.17 moles x 64.51 g/mole = 10.97 g (if yield is 100 %)
If yield is 89.4 % mass of ethyl chloride = 10.97 g x 0.894 = 9.81 g