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Answer to Question #78022 in General Chemistry for Chloe Lozano
Question #78022
A liquid has a specific heat of 2.81 J/goC, a mass of 90.0 g, and an initial temperature of 25.0 oC. What is the new temperature of the liquid if 2,350 J of energy are removed from it?
A. 1.57 oC
B. 9.30 oC
C. 15.7 oC
D. 34.3 oC
E. None of the Above
A. 1.57 oC
B. 9.30 oC
C. 15.7 oC
D. 34.3 oC
E. None of the Above
Expert's answer
Answer: D.
q = m×c×(T2-T1)
2350 = 90.0 g × 2.81 J/g*C × (T2-25.0 C)
T2 = 34.3 C
q = m×c×(T2-T1)
2350 = 90.0 g × 2.81 J/g*C × (T2-25.0 C)
T2 = 34.3 C
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