Answer to Question #77962 in General Chemistry for Chloe Lozano

Question

use the following information: A container has 8360.0 torr of Nitrogen, 5.00 atm of Oxygen, 101.1 kPa of Argon, and 760.0 mm Hg of Carbon Dioxide.

what is the mole fraction of Carbon Dioxide?

A. 0.056
B. 0.067
C. 0.256
D. 0.667
E. 0.757

Answer 1

8360 torr x 1 atm/760 torr = 11 atm N2
5 atm O2
101.1 kPa x 1 atm/101.32 = 0.998 atm Ar
760 mm Hg x 1 atm/760 mm Hg = 1 atm CO2
Total Pressure = 11 atm + 5 atm + 0.998 atm +1 atm = 17.998 atm
mole fraction CO2 = 1 atm/17.998 = 0.056 (A)