Question #77962
use the following information: A container has 8360.0 torr of Nitrogen, 5.00 atm of Oxygen, 101.1 kPa of Argon, and 760.0 mm Hg of Carbon Dioxide.
what is the mole fraction of Carbon Dioxide?
A. 0.056
B. 0.067
C. 0.256
D. 0.667
E. 0.757
what is the mole fraction of Carbon Dioxide?
A. 0.056
B. 0.067
C. 0.256
D. 0.667
E. 0.757
Expert's answer
8360 torr x 1 atm/760 torr = 11 atm N2
5 atm O2
101.1 kPa x 1 atm/101.32 = 0.998 atm Ar
760 mm Hg x 1 atm/760 mm Hg = 1 atm CO2
Total Pressure = 11 atm + 5 atm + 0.998 atm +1 atm = 17.998 atm
mole fraction CO2 = 1 atm/17.998 = 0.056 (A)
5 atm O2
101.1 kPa x 1 atm/101.32 = 0.998 atm Ar
760 mm Hg x 1 atm/760 mm Hg = 1 atm CO2
Total Pressure = 11 atm + 5 atm + 0.998 atm +1 atm = 17.998 atm
mole fraction CO2 = 1 atm/17.998 = 0.056 (A)
Learn more about our help with Assignments: Chemistry
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
#339914 on Dec 2023
#339914 on Dec 2023
Comments
Dear Chloe Lozano, You're welcome. We are glad to be helpful. If you liked our service please press like-button beside answer field. Thank you!
thank you so much