Question #77897
use the following information: A container has 8360.0 torr of Nitrogen, 5.00 atm of Oxygen, 101.1 kPa of Argon, and 760.0 mm Hg of Carbon Dioxide.
what is the mole fraction of Nitrogen?
A. 0.056
B. 0.167
C. 0.667
D. 0.611
E. 0.733
what is the mole fraction of Nitrogen?
A. 0.056
B. 0.167
C. 0.667
D. 0.611
E. 0.733
Expert's answer
Answer: D.
8360 torr x 1 atm/760 torr = 11 atm N2
5 atm O2
101.1 kPa x 1 atm/101.32 = 0.998 atm CO2
760 mm Hg x 1 atm/760 mm Hg = 1 atm
Total Pressure = 11 atm + 5 atm + 0.998 atm +1 atm = 17.998 atm
mole fraction N2 = 1.1 atm/17.998 = 0.611
8360 torr x 1 atm/760 torr = 11 atm N2
5 atm O2
101.1 kPa x 1 atm/101.32 = 0.998 atm CO2
760 mm Hg x 1 atm/760 mm Hg = 1 atm
Total Pressure = 11 atm + 5 atm + 0.998 atm +1 atm = 17.998 atm
mole fraction N2 = 1.1 atm/17.998 = 0.611
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#339914 on Dec 2023
#339914 on Dec 2023
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