Answer to Question #77894 in General Chemistry for keith

Question

Four moles of carbon monoxide (CO) has 48 grams of carbon (C) and 64 grams of oxygen (O). What is the percent composition of carbon in carbon monoxide?

Answer 1

Answer:
m (CO) = n*M, where n is the amount of substance, mole, M is the molar mass, g/mole
m (CO) = 4*28 = 112 g
% C = m (C)*100% / m (CO) = 48*100 % / 112 = 42.8 %