Question #77894
Four moles of carbon monoxide (CO) has 48 grams of carbon (C) and 64 grams of oxygen (O). What is the percent composition of carbon in carbon monoxide?
Expert's answer
Answer:
m (CO) = n*M, where n is the amount of substance, mole, M is the molar mass, g/mole
m (CO) = 4*28 = 112 g
% C = m (C)*100% / m (CO) = 48*100 % / 112 = 42.8 %
m (CO) = n*M, where n is the amount of substance, mole, M is the molar mass, g/mole
m (CO) = 4*28 = 112 g
% C = m (C)*100% / m (CO) = 48*100 % / 112 = 42.8 %
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#339914 on Dec 2023
#339914 on Dec 2023