Answer to Question #77863 in General Chemistry for Andrew

Question

If 30g of HCl is reacted with excess NaOH, and 10g of NaCl is produced, what is the theoretical yield of the experiment?

Answer 1

HCl + NaOH → NaCl + H2O

n(HCl) = m/M = 30g/36.5g/mol = 0.82 mol

n(NaCl) = n(HCl) = 0.82 mol

M(NaCl) = 23 + 35.5 = 58.5 g/mol

m(NaCl) = n*M = 0.82mol*58.5g/mol = 47.97 g

47.97 g of NaCl with excess NaOH will theoretically produce 30 g of HCl.