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Answer to Question #76817 in General Chemistry for maria
Question #76817
How many grams of LiBr are needed to prepare 125 g of 20% solution?
Expert's answer
Answer:
% by mass = (mass of solute/mass of solution) * 100 %
20 % = (mass of solute/125)*100%
mass of solute = 25 g
% by mass = (mass of solute/mass of solution) * 100 %
20 % = (mass of solute/125)*100%
mass of solute = 25 g
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