How many grams of methamphetamine (C10H15N) would be needed to prepare 100 ml of a solution of 0.10 M methamphetamine?
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Expert's answer
2018-04-26T07:42:09-0400
Answer: Cm = n/V, where n is amount of substance, mole, V is volume of solution, litre, Cm is molar concentration, mole/litre n = Cm*V n = 0.1*0.1 = 0.01 mole m = M*n, where M is molar mass (149 g/mole) m = 149*0.01 = 1.49 g
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