Answer to Question #76494 in General Chemistry for Anna Circosta
What mass of gold contains twice as many atoms as 1.59g of silver?
1
2018-04-25T08:41:35-0400
m(Ag) = 1.59 g
n(Ag) = m/M = 1.59 g / 107.87 g/mol = 0.01474 mol
N(Ag) = n*NA = 0.01474mol*6.02·1023atoms/mol = 8.873·1021 atoms
N(Au) = 2*8.873·1021 = 17.746·1021 atoms
n(Au) = N/NA = 17.746·1021 atoms / 6.02·1023 atoms/mol = 0.02948 mol
m(Au) = n*M = 0.02948 mol*196.97 g/mol = 5.81 g
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