What volume of ethylene glycol, an anti-freezing agent, C2H6O2 (p=1.12g/ml) must be added to 20.0ml of water in a car radiator to produce a solution that freezes at -10.0C?
1
Expert's answer
2018-04-11T08:10:37-0400
Answer: 5.95 ml
delta Tf = Kf × m
where delta Tf = depression in freezing point
since pure water freezes at 0 degree C but this solution is freezing at -10.0 ...so delta Tf = 10.0
Kf = 1.86 deg /m
m = molality of solute = n of moles of solute/amount of solvent in kg
n of moles of C2H6O2 (solute) = given weight of C2H6O2/molecular mass = w/M
M for C2H6O2 = 62 g/mole
so n of moles = w/62
volume of water = 20 ml
density of water = mass of water/volume of water
so mass of water = density of water × volume of water
so mass of water = 1 × 20 = 20 g
mass of water in kg (solvent) = 0.02 kg
so molality = w/62 / 0.02 = w/1.24
delta Tf = Kf × m
10 = 1.86 × w/1.24
w = 10 × 1.24 /1.86 = 6.67 g V = m/p V = 6.67/1.12 = 5.95 ml
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