If this reaction produced 51.4 g of KCl, how much O2 was produced (in grams)?
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Expert's answer
2018-04-07T08:18:11-0400
2KClO3 ----> 2KCl +3O2 According to the equation 2 moles of KCl and 3 moles of O2 are produced after the decomposition of 2 moles of KClO3. Find how many moles of KCl were produced: ν = m/M = 51.4/74.5 = 0.69 (mole); Find how many moles of O2 were produced: ν = 0.69 × 1.5 = 1.035 (mole) ; Find the mass of O2 : m = ν × M = 1.035 × 32 = 33.12 (g) Answer 33.12 g of O2 were produced.
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