Answer to Question #75550 in General Chemistry for Lilit

Question #75550
Given that 4 NH3 + 5 O2 → 4 NO + 6 H2O, when 4.50 mol of H2O are formed, the amount of NO formed is:
1
Expert's answer
2018-04-05T07:45:13-0400
(4.50 mol H2O) x (4 mol NO/ 6 mol H2O) = 3.00 mol NO

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