Answer to Question #75539 in General Chemistry for Chloe Lozano

Question

For the reaction KOH (aq) + HCN (aq) → H2O (l) + KCN (aq), what volume of HCN at 2.00 M would be required in order to make 33.0 g of KCN, when there is more HCN than needed?

A. 25.4 L
B. 2.54 L
C. 0.254 L
D. 0.0254 L
E. None of the Above

Answer 1

Calculate moles of KCN = 33.0 g/ 65.12 g/mole = 0.51 mole
From the reaction stoichiometry moles of HCN =0.51 mole
Volume of HCN = 0.51 moles/ (2.00 moles/L) = 0.25 L