For the reaction 3NaSO4 (aq) + 2Al(NO3)3 (aq) → Al2(SO4)3 (s) + 6 NaNO3 (aq), adding 960.0 ml of 5.20 M Aluminum Nitrate to excess Sodium Sulfate will produce how many grams of Aluminum Sulfate?
A. 4.99 mol Al(NO3)3
B. 856 mol Al2(SO4)3
C. 296.4 g Al2(SO4)3
D. 499 g Al(NO3)3
E. None of the Above
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