Answer to Question #75275 in General Chemistry for Lilit

Question #75275

How many grams are there in 0.0457 moles of (NH4)2S?

Expert's answer

n((NH4)2S) = 0.0457 moles

M((NH4)2S) = 14*2 + 1*8 + 32 = 68 g/mol

m((NH4)2S) = n*M = 0.0457mol*68g/mol = 3.1076 g

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