Question #75274
I have 50.0 grams of SO3. a) how many molecules of SO3 are in this sample? b) how many oxygen atoms are in this sample?
Expert's answer
m(SO3) = 50 g
n(SO3) = m/M = 50 g / 80 g/mol = 0.625 mol
N(SO3) = n*NA = 0.625 mol*6.02*10^23mol-1 = 3.7625*10^23 molecules
N(O) = 3*3.7625*10^23 = 11.2875*10^23 atoms
n(SO3) = m/M = 50 g / 80 g/mol = 0.625 mol
N(SO3) = n*NA = 0.625 mol*6.02*10^23mol-1 = 3.7625*10^23 molecules
N(O) = 3*3.7625*10^23 = 11.2875*10^23 atoms
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#339914 on Dec 2023
#339914 on Dec 2023
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A sample of 8.5 g NH3 on oxidation produces 4.5 g of NO. Calculate the percent yield. Reaction: 4 NH3 + 5 O2 → 4 NO + 6 H2O