6Na + Fe2O3 --> 3Na2O + 2Fe If you are provided 200g of sodium and 250 grams of iron(III) oxide, which substance is the limiting reactant? Explain your reasoning.
1
Expert's answer
2018-03-29T08:00:02-0400
6Na + Fe2O3 → 3Na2O + 2Fe
n(Na) = m/M = 200g/23g/mol = 8.7 moles
n(Fe2O3) = 250g/160g/mol = 1.6 moles
The limiting reactant in a chemical reaction is the substance which is totally consumed when the chemical reaction is complete.
From our calculation, 8.7 moles of Na reacted with only 8.7/6 = 1.45 moles out of 1.6 moles of Fe2O3. Fe2O3 is the excess reactant because what was given is more than what reacted and therefore Na is the limiting reactant.
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
Finding a professional expert in "partial differential equations" in the advanced level is difficult.
You can find this expert in "Assignmentexpert.com" with confidence.
Exceptional experts! I appreciate your help. God bless you!
Comments
Leave a comment