Question

For the following chemical reaction, how many moles of calcium carbonate will be produced from 85.5 g of sodium carbonate?
Na2CO3+Ca(NO3)2---->CaCO3+2NaNO3

Answer 1

Na2CO3 + Ca(NO3)2  CaCO3 + 2NaNO3
1. Find chemical amount of sodium carbonate (Na2CO3):
m= Mn, then n= m/M;
M(Na2CO3) = 22.992 + 12.01+16.003 = 105.99 (g/mol);
n(Na2CO3) = 85.5 /105.99 =0.81 (mole).
2. Find chemical amount of calcium carbonate (CaCO3):
According to equation of chemical reaction 1 mole of Na2CO3 gives 1 mole of CaCO3, i.e.
n(Na2CO3) = n(CaCO3);
n(CaCO3) = 0.81 mol
Answer: 0.81 mol