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Answer to Question #74672 in General Chemistry for Shayne F.
Question #74672
What is the percentage of MnCl2 in MnCl2 2H2O?
Expert's answer
Answer
M(MnCl 2 ) = 55 + 35.5x2 = 126 g/mol
M(MnCl 2 x2H 2 O) = (55 + 35.5x2) + (2x18) = 162 g/mol
w(MnCl 2 ) = 126/162x100% = 77.78%
M(MnCl 2 ) = 55 + 35.5x2 = 126 g/mol
M(MnCl 2 x2H 2 O) = (55 + 35.5x2) + (2x18) = 162 g/mol
w(MnCl 2 ) = 126/162x100% = 77.78%
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