Question #74610
Balanced chemical equations for the following reactions:
1) lithium metal(s) + water(l) --> lithium hydroxide (aq) + hydrogen
2) lead(ii) nitrate(aq) + sodium iodide (aq) --> lead (ii) iodide (s) + sodium nitrate(aq)
3) acetic acid (aq) + barium hydroxide (aq) --> barium acetate (aq) + water(l)
I'm confused on how to solve it. And my teacher is not doing a good job with explaining how to solve this
1) lithium metal(s) + water(l) --> lithium hydroxide (aq) + hydrogen
2) lead(ii) nitrate(aq) + sodium iodide (aq) --> lead (ii) iodide (s) + sodium nitrate(aq)
3) acetic acid (aq) + barium hydroxide (aq) --> barium acetate (aq) + water(l)
I'm confused on how to solve it. And my teacher is not doing a good job with explaining how to solve this
Expert's answer
Answer:
1) 2Li(s) + 2H2O(l) → 2LiOH(aq) + H2(g)
2) Pb(NO3)2(aq) + 2NaI(aq) → PbI2(s) + 2NaNO3(aq)
3) 2CH3COOH(aq) + Ba(OH)2(aq) → Ba(CH3COO)2(aq) + 2H2O(l)
1) 2Li(s) + 2H2O(l) → 2LiOH(aq) + H2(g)
2) Pb(NO3)2(aq) + 2NaI(aq) → PbI2(s) + 2NaNO3(aq)
3) 2CH3COOH(aq) + Ba(OH)2(aq) → Ba(CH3COO)2(aq) + 2H2O(l)
