Question

an aqueous sodium chloride solution is electrolyzed using a current of 2.05 a. How much time is required to collect 19.5 L of chlorine if the gas is collected over water at 20C and then the total pressure is 109.9 kpa? Express answer in minutes.

Answer 1

Answer on Question #74509, Chemistry / General Chemistry:

An aqueous sodium chloride solution is electrolyzed using a current of 2.05 a. How much time is required to collect 19.5 L of chlorine if the gas is collected over water at 20C and then the total pressure is 109.9 kpa? Express answer in minutes.

Solution.

$$I = 2.05\,A$$ $$F = 96500$$ $$V(Cl_2) = 19.5\,L$$ $$T = 293\,K$$ $$P = 109.9\,kpa$$ $$t - ?$$

The amount of chlorine can be calculated:

$$pV = \frac{m}{M} RT = vRT$$ $$v = \frac{pV}{RT}$$ $$m = \frac{pV \cdot M}{RT}$$

The Faraday law for electrolysis:

$$m = \frac{AIt}{nF}$$

And: $\frac{pV \cdot M}{RT} = \frac{AIt}{nF}$

Then:

$$\frac{pV \cdot M}{RT} = \frac{MIt}{4F}$$ $$\frac{pV}{RT} = \frac{It}{4F}$$ $$t = \frac{4pV \cdot F}{IRT}$$

The time of electrolysis:

$$t = \frac{4 \cdot 109900 \cdot 19.5 \cdot 10^{-3} \cdot 96500}{2.05 \cdot 8.314 \cdot 293} = 162478\,s$$ $$t = 2708\,\text{min}$$

Answer: $t = 2708\,\text{min}$

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