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Answer to Question #74085 in General Chemistry for cameron
Question #74085
If the pressure of a 2.00 L sample of gas is 50.0 kPa, what pressure does the gas exert if its volume is decreased to 20.0 mL?
Expert's answer
Boyle's Law is
P1V1 = P2V2
P2 = P1·V1/V2
P1 = 50 kPa
V1 = 2.00 L
V2 = 20.0 mL = 0.02 L
P2 = 50kPa·2L/0.02L = 5000 kPa = 5 MPa
P1V1 = P2V2
P2 = P1·V1/V2
P1 = 50 kPa
V1 = 2.00 L
V2 = 20.0 mL = 0.02 L
P2 = 50kPa·2L/0.02L = 5000 kPa = 5 MPa
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