Answer to Question #74085 in General Chemistry for cameron

Question #74085

If the pressure of a 2.00 L sample of gas is 50.0 kPa, what pressure does the gas exert if its volume is decreased to 20.0 mL?

Expert's answer

Boyle's Law is

P1V1 = P2V2

P2 = P1·V1/V2

P1 = 50 kPa

V1 = 2.00 L

V2 = 20.0 mL = 0.02 L

P2 = 50kPa·2L/0.02L = 5000 kPa = 5 MPa

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