Answer to Question #73876 in General Chemistry for Simon

Question

You want to prepare 50cm^3 of 0.1M NaOH from exactly 50% (wt/wt) NaOH solution. What volume of the 50% solution is required?

Answer 1

The solution contains: 0.1 mol/L ∙ 0.050 L = 0.005 mol of NaOH or:
0.005 mol ∙ 40 g/mol = 0.2 g
50% means: 100 g of the solution contains 50 g of NaOH, so 0.2 g ∙ 2 = 0.4 g or:
V = 0.4 g / 1,5253 g/mL ≈ 0.26 mL.
Answer: 0.26 mL.