Vanillin, the dominant flavoring in vanilla, contains C, H,
and O. When 1.05 g of this substance is completely com-
busted, 2.43 g of CO2 and 0.50 g of H2O are produced. What
is the empirical formula of vanillin?
1
Expert's answer
2018-02-15T03:28:44-0500
.m (vanillin)=1.05g .m (CO2)=2.43 g .m(H2O)=0.5 g the empirical formula of vanillin? Mr (CO2)= Ar (С) +2 Ar (O)= 12+ 2*16=44 Find amount of substances of CO2 : n (CO2)=m(CO2)/Mr(CO2)=2.43/44 =0.055 mol .n(C) = n(CO2)=0.055 mol Find amount of substances of H2O: n(H2O)=m(H2O)/Mr(H2O)=0.5/18=0.028 Mr (H2O)= 2Ar(H)+Ar(O)= 2+16=18 .n(H)=2n (H20)= 2*0.028=0.056 mol .n(C) :n(H)=0.055 :0.056=1:1 the empirical formula is CH
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