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Answer to Question #72696 in General Chemistry for Jepoy Eskabarte
Question #72696
Use Boyle's, Charles's, Gay-Lussac's Law to calculate the missing value of the following:
v1= 250 ml, t1=?, v2=400 ml, t2=298 Kelvin
v1= 250 ml, t1=?, v2=400 ml, t2=298 Kelvin
Expert's answer
T1/V1 = T2/V2
T1 = (V1·T2)/V2
T1 = (250ml·298K)/400ml = 186.25 K
T1 = (V1·T2)/V2
T1 = (250ml·298K)/400ml = 186.25 K
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