Question

A gas grill burns Propane (C3H8) in the presence of more than sufficient Oxygen (O2). This reaction produces water vapor and Carbon Dioxide. The temperature and pressure conditions are such that 1 mole of each gas occupies 1 liter of volume.

What is the balanced equation for this reaction?

A. C3H8 + 4O2 → 2CO2 + 4H2O
B. C3H8 + 5O2 → 3CO2 + 4H2O
C. 2C3H8 + 6O2 → 6CO2 + 8H2O
D. 2C3H8 + 5O2 → 6CO2 + 4H2O
E. None of the Above

Answer 1

Question #72655, Chemistry / General Chemistry / Completed

A gas grill burns Propane $(\mathrm{C}_3\mathrm{H}_8)$ in the presence of more than sufficient Oxygen $(\mathrm{O}_2)$ . This reaction produces water vapour and Carbon Dioxide. The temperature and pressure conditions are such that 1 mole of each gas occupies 1 litre of volume.

What is the balanced equation for this reaction?

A. $\mathrm{C}3\mathrm{H}8 + 4\mathrm{O}2 \rightarrow 2\mathrm{CO}2 + 4\mathrm{H}2\mathrm{O}$

B. $\mathrm{C}3\mathrm{H}8 + 5\mathrm{O}2 \rightarrow 3\mathrm{CO}2 + 4\mathrm{H}2\mathrm{O}$

C. $2 \mathrm{C} 3 \mathrm{H} 8 + 6 \mathrm{O} 2 \rightarrow 6 \mathrm{CO} 2 + 8 \mathrm{H} 2 \mathrm{O}$

D. $2 \mathrm{C} 3 \mathrm{H} 8 + 5 \mathrm{O} 2 \rightarrow 6 \mathrm{CO} 2 + 4 \mathrm{H} 2 \mathrm{O}$

E. None of the Above

Answer

B. $\mathrm{C}3\mathrm{H}8 + 5\mathrm{O}2 \rightarrow 3\mathrm{CO}2 + 4\mathrm{H}2\mathrm{O}$

Before reaction: After reaction:

C 3 3

H 8 8

0 10 10

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