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Answer to Question #72408 in General Chemistry for Alexa Arbolante
Question #72408
AgNO3+NH4Cl --> AgCl+NH4NO3. If you have 50.26g of AgNO3, how many grams of NH4NO3 can be produced?
Expert's answer
AgNO3+NH4Cl = AgCl+NH4NO3
n(AgNO3) = n(NH4NO3)
n(AgNO3) = 50,26 / 169,87 = 0,296 mol = n(NH4NO3)
m(NH4NO3) = n(NH4NO3) * Mr(NH4NO3)
m(NH4NO3) = 0,296 * 80 = 23,67 g
n(AgNO3) = n(NH4NO3)
n(AgNO3) = 50,26 / 169,87 = 0,296 mol = n(NH4NO3)
m(NH4NO3) = n(NH4NO3) * Mr(NH4NO3)
m(NH4NO3) = 0,296 * 80 = 23,67 g
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