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Answer to Question #72055 in General Chemistry for Jasmin
Question #72055
find the momentum of an electron with a wavelength of 456 no
Expert's answer
Answer:
p = h/ λ
h = 6.62606957(29)×10^−34 J·s.
p = 6.62606957(29)×10^−34 / 456 ·10-9 = 0.014·10^-25
p = h/ λ
h = 6.62606957(29)×10^−34 J·s.
p = 6.62606957(29)×10^−34 / 456 ·10-9 = 0.014·10^-25
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