Answer to Question #71692 in General Chemistry for nik

Question

Calculate the heat required to vaporize 7.87 g of benzene at its normal boiling point.

Heat of vaporization (benzene) = 30.7 kJ/mol

Heat = kJ

Answer 1

Solution:
Molecular weight of benzene: 78.11 g/mol
Amount of benzene: 7.87 / 78.11 = 0.1 mol
Energy needed (heat): 0.1 ∙ 30.7 = 3.07 kJ
Answer:
Heat = 3.07 kJ