3A + 6B → 3D ΔH = –400 kJ
E + 2F → A ΔH = –115.0 kJ
C → E + 3D ΔH = –68.2 kJ
Suppose the first equation is reversed and multiplied by 1/6, the second and third equations are divided by 2, and the three adjusted equations are added. What is the net reaction and what is the overall heat of this reaction?
Enter the reaction equation without spaces.
Net reaction: →
ΔH = kJ
1
Expert's answer
2017-11-30T01:59:06-0500
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