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Answer to Question #71478 in General Chemistry for marcia
Question #71478
When 250.0 mg of eugenol was added to 100.0g of camphor, it lowered the freezing point of camphor by 0.620C. Calculate the molar mass of eugenol.
Expert's answer
ΔT = Cm · Kf
Сm = n/m n = m/M M (C10H12O2) = m/n
Kf (camfora) = 4.0
Cm (C10H12O2) = ΔT/Kf = 0.62/4 = 0.155 m
n (C10H12O2) = 0.155 · 100 = 15.5 mol
M (C10H12O2) = 250 / 15.5 = 161 g/mol
Сm = n/m n = m/M M (C10H12O2) = m/n
Kf (camfora) = 4.0
Cm (C10H12O2) = ΔT/Kf = 0.62/4 = 0.155 m
n (C10H12O2) = 0.155 · 100 = 15.5 mol
M (C10H12O2) = 250 / 15.5 = 161 g/mol
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Dear marcia, please use panel for submitting new questions
a) What is meant by the phrase “colligative properties”? b) How many moles of ions are present in a solution containing 0.10mol Na2SO4 assuming complete dissociation into Na+ and SO42- ions? Estimate the van’t Hoff factor.
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