Answer to Question #71160 in General Chemistry for Matt

Question

The concentration of the standard in the first well is 90 ngmL. The aliquot volume is 100uL. The volume of diluent in well 2-8 is 100 uL each. What is the concentration of the standard in well 8?

Answer 1

In 1 well:
m = 90 ng
V = 1 mL
In 8 well:
m = 90 ng
V = 1 ml + 100 uL = 1.1 mL
C = m / V = 90 ng / 1.1 mL = 81.81 ng/mL
Answer:
C = 81.81 ng/mL