The concentration of the standard in the first well is 90 ngmL. The aliquot volume is 100uL. The volume of diluent in well 2-8 is 100 uL each. What is the concentration of the standard in well 8?
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Expert's answer
2017-11-18T12:34:07-0500
In 1 well: m = 90 ng V = 1 mL In 8 well: m = 90 ng V = 1 ml + 100 uL = 1.1 mL C = m / V = 90 ng / 1.1 mL = 81.81 ng/mL Answer: C = 81.81 ng/mL
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